The wavelength of {K_{alpha }} X-rays produce | vedclass

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(B) For the ${K_{\alpha }}$ $X$-ray line,Moseley's law is given by:$\frac{1}{\lambda} = R(Z - 1)^2 \left[ \frac{1}{1^2} - \frac{1}{2^2} \right] = \fra

Vedclass · Accepted Answer

$41$

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(B) For the ${K_{\alpha }}$ $X$-ray line,Moseley's law is given by:$\frac{1}{\lambda} = R(Z - 1)^2 \left[ \frac{1}{1^2} - \frac{1}{2^2} ight] = \frac{3R}{4}(Z - 1)^2$Given $\lambda = 0.76 \, \mathring{A} = 0.76 	imes 10^{-10} \, m$ and Rydberg constant $R \approx 1.097 	imes 10^7 \, m^{-1}$.Substituting the values:$\frac{1}{0.76 	imes 10^{-10}} = \frac{3}{4} 	imes 1.097 	imes 10^7 	imes (Z - 1)^2$$1.315 	imes 10^{10} = 0.82275 	imes 10^7 	imes (Z - 1)^2$$(Z - 1)^2 = \frac{1.315 	imes 10^{10}}{0.82275 	imes 10^7} \approx 1598.3$$Z - 1 \approx \sqrt{1600} = 40$$Z = 41$.

The wavelength of ${K_{\alpha }}$ $X$-rays produced by an $X$-ray tube is $0.76 \, \mathring{A}$. The atomic number of the anticathode material is:

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